document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=422314>Question 422314</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Lucas ran away from home at 7:15 p.m. running at a rate of 5 kph. His father set out after him 15/2 hours later. At what time did the father overtake the son if he was able to pursue at the rate of 8 kph? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #294776 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=294776\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Lucas speed	5	kph			<BR>\n" );
document.write( "father's rate	8	kph			<BR>\n" );
document.write( "					<BR>\n" );
document.write( "Difference in time=	7.5 hours	(15/2) hours	<BR>\n" );
document.write( "Lucas  will have covered 37.5 km	father starts	<BR>\n" );
document.write( "					<BR>\n" );
document.write( "catch up distance=37.5	km		<BR>\n" );
document.write( "catch up speed =	8-5 kph	<BR>\n" );
document.write( "catch up speed =	3 kph		<BR>\n" );
document.write( "					<BR>\n" );
document.write( "Catchup time = catchup distance/catch up speed					<BR>\n" );
document.write( "catch up time=37.5/3	<BR>\n" );
document.write( "catch up time= 12.5 hours		<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );