document.write( "Question 422302: Peter can buy a high-effciency furnance for $2250 that costs $412 per year to operate. He may also buy a standard furnance for $1710 that costs $466 per year to operate. Find how long it will take for the two furnances to have the same cost. If Peter intends to live in his house for 7 years which furnance should he buy? What if he wants to live in his house for 20 years? \n" ); document.write( "

Algebra.Com's Answer #294765 by mananth(16946) $\"\"$ $\"About$

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High efficiency furnace---$2250 + $412 x : x is the number of years
\n" ); document.write( "Standard furnace $1710 + 466x\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "Cost equal\r
\n" ); document.write( "\n" ); document.write( "2250+412x= 1710+466x
\n" ); document.write( "2250-1710=466x-412x
\n" ); document.write( "540=54x
\n" ); document.write( "540/54 = x
\n" ); document.write( "x= 10 years when cost will be equal.\r
\n" ); document.write( "\n" ); document.write( "...
\n" ); document.write( "For x less than 10 years Standard furnace is economical\r
\n" ); document.write( "\n" ); document.write( "Plug 20 for both options
\n" ); document.write( "2250+412*20 =10,490 high efficiency
\n" ); document.write( "1710+466*20=11,030 standard
\n" ); document.write( "You may decide \n" ); document.write( "

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