document.write( "Question 421985: Solve on indicated interval: 0°≤Θ<2π Find EXACT answers.\r
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Algebra.Com's Answer #294734 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
Rewrite \"sin%282theta%29\" as \"2sin%28theta%29cos%28theta%29\". The equation becomes\r
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\n" ); document.write( "\n" ); document.write( "\"2sin%5E2%28theta%29+cos%28theta%29+=+cos%28theta%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"2sin%5E2%28theta%29+cos%28theta%29+-+cos%28theta%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"cos%28theta%29%282sin%5E2%28theta%29+-+1%29+=+0\". Either \"cos%28theta%29+=+0\" or \"2sin%5E2%28theta%29+-+1+=+0\" --> \"sin%5E2%28theta%29+=+1%2F2\", \"sin%28theta%29+=+sqrt%282%29%2F2\" or \"sin%28theta%29+=+-sqrt%282%29%2F2\".\r
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\n" ); document.write( "\n" ); document.write( "We evaluate the arcsine or arc-cosine of each to produce all possible values of \"theta\", which are \"pi%2F2\", \"3pi%2F2\", as well as \"pi%2F4\", \"7pi%2F4\", \"3pi%2F4\", \"5pi%2F4\".
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