document.write( "Question 422162: against the wind a small plane flew 21 miles in 1 hr and 10 minutes, the return trip only took 50 minutes. what was the speed of the wind, what was the speed of the plane in still air \n" ); document.write( "
Algebra.Com's Answer #294709 by mananth(16946)![]() ![]() You can put this solution on YOUR website! against wind 1 1/6 hours \n" ); document.write( "with wind 5/6 hours \n" ); document.write( " \n" ); document.write( "Distance = same= 21 miles \n" ); document.write( "plane speed =x \n" ); document.write( "wind speed =y \n" ); document.write( "t=d/r \n" ); document.write( "21/(x-y)=1.17 \n" ); document.write( "1.17(x-y)=21.00 \n" ); document.write( "1.17x-1.17y=21 ....................1 \n" ); document.write( "21/(x+y)= 5/6 \n" ); document.write( " 5/6(x+y )=21 \n" ); document.write( " 5/6x+ 5/6y=21 ...............2 \n" ); document.write( "Multiply (1) by 5 \n" ); document.write( "Multiply (2) by 8 \n" ); document.write( "we get \n" ); document.write( "5.83x-5.83y=105 \n" ); document.write( "6.67x+6.67y=168 \n" ); document.write( "12.5x=273 \n" ); document.write( "/12.5 \n" ); document.write( "x=21.84 mph plane speed \n" ); document.write( " \n" ); document.write( "plug value of x in (1) \n" ); document.write( "1.17x-1.17y=21 \n" ); document.write( "25.48-1.17y=21 \n" ); document.write( "-1.17y=21-25.48 \n" ); document.write( "-1.17y=-4.48 \n" ); document.write( "y=3.84 mph wind speed \n" ); document.write( " \n" ); document.write( " |