document.write( "Question 422184: if the measure of the two opposite angles of a parallogram are: 3x + 40 and x + 50, what is the value of x and the measure of its angle? \n" ); document.write( "

Algebra.Com's Answer #294703 by shree840(260) $\"\"$ $\"About$

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Two opposite angles of a parallelogram\r
\n" ); document.write( "\n" ); document.write( "two adjacent angles are supplementary.
\n" ); document.write( "If you draw a parallelogram A --------------B
\n" ); document.write( " - -
\n" ); document.write( " - -
\n" ); document.write( " D------------C
\n" ); document.write( "let us say angle dab is 3x+40 angle DCB = x+50\r
\n" ); document.write( "\n" ); document.write( "angle ADC =180-(3x+40)
\n" ); document.write( "two adjacent angles are supplementary\r
\n" ); document.write( "\n" ); document.write( "so 180-(3x+40)+x+50=180\r
\n" ); document.write( "\n" ); document.write( "180 cancels.
\n" ); document.write( "-3x-40+x+50=0
\n" ); document.write( "-2x+10=0
\n" ); document.write( "2x=10
\n" ); document.write( "x=5
\n" ); document.write( "angles are 3x+40=3*5+40=55
\n" ); document.write( "x+50=55 \n" ); document.write( "

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