document.write( "Question 422177: i am lost how do i solve x squared -2x=24 by factoring \n" ); document.write( "
Algebra.Com's Answer #294699 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+-2x=24\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+-2x+-24=0\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+-2x+-24=0\".....replace \"-2x\" with \"4x-6x\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2+%2B4x-6x+-24=0\"......group the first two terms together and the last two terms together like this:\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2+%2B4x%29%2B%28-6x+-24%29=0\"....factor a x out of the first group and factor a -6 out of the second group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%28x+%2B4%29-6%28x+%2B4%29=0\"....we have a common term (x +4) we can combine the two terms\r
\n" ); document.write( "\n" ); document.write( "\"%28x-6%29%28x+%2B4%29=0\"....now, a product is equal to zero if one or both multiplicands are equal to zero\r
\n" ); document.write( "\n" ); document.write( "\"x-6=0\"....->...\"x=6\"\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "\"x%2B4=0\"....->...\"x=-4\"\r
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