document.write( "Question 422133: A student invested $5000 in two different savings accounts. The first account pays an annual interest rate of 3%. The second account pays an annual interest rate of 4%. At the end of the year, she had earned $185 in interest. How much money did she invest in each account? \n" ); document.write( "
Algebra.Com's Answer #294688 by mananth(16946)\"\" \"About 
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3.00% per annum ------------- x
\n" ); document.write( "4.00% per annum ------------ y
\n" ); document.write( "total investment 5000
\n" ); document.write( "Interest----- $185.00
\n" ); document.write( "...
\n" ); document.write( "x+y=5000 ------------------------1
\n" ); document.write( "3.00%x+4.00%y=$185.00
\n" ); document.write( "Multiply by 100
\n" ); document.write( "3x+4y=$18,500.00 --------2
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\n" ); document.write( "Multiply (1) by -3
\n" ); document.write( "we get
\n" ); document.write( "-3x-3y= -15000
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\n" ); document.write( "Add this to (2)
\n" ); document.write( "
\n" ); document.write( "y=$3,500.00 investment at 4%
\n" ); document.write( "Balance $1,500.00 investment at 3%
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