document.write( "Question 422161: I need help on figuring this problem out please. The height of a triangle is three feet longer than the base. The area of the triangle is 44 square feet. Find the height and base of the triangle \n" ); document.write( "

Algebra.Com's Answer #294682 by stanbon(75887) $\"\"$ $\"About$

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I need help on figuring this problem out please. The height of a triangle is three feet longer than the base. The area of the triangle is 44 square feet. Find the height and base of the triangle
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\n" ); document.write( "Area = (1/2)(base)*(height)
\n" ); document.write( "44 = (1/2)(x)(x+3)
\n" ); document.write( "22 = x^2+3x
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\n" ); document.write( "x^2+3x-22 = 0
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\n" ); document.write( "x = [-3 +- sqrt(9-4*-22)]/2
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\n" ); document.write( "x = [-3 +- sqrt(97)]/2
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\n" ); document.write( "Positive Solution:
\n" ); document.write( "x = [-3+sqrt(97)]/2 (base)
\n" ); document.write( "---
\n" ); document.write( "x = [-3+sqrt(97) +6]/2
\n" ); document.write( "x = [3+sqrt(97)]/2 (height)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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