document.write( "Question 44501: A business discovers a linear relationship between the number of shirts it can sell and the price per shirt. In particular, 20,000 shirts can be sold at $19 each and 2000 of the same shirts can be sold at $55 each. Write the slope-intercept equation of the demand line through the ordered pairs (20,000 shirts, $19) and (2000 shirts, $55). Then determine the number of shirts that can be sold at $50 each. \n" ); document.write( "
Algebra.Com's Answer #29465 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Write the slope-intercept equation of the demand line through the ordered pairs (20,000 shirts, $19) and (2000 shirts, $55). Then determine the number of shirts that can be sold at $50 each.\r \n" ); document.write( "\n" ); document.write( "slope = (55-19)/(2000-20000)= 36/-18000= -1/500\r \n" ); document.write( "\n" ); document.write( "Form of the linear is y=mx+b where y=55, x=2000, m=-1/500; find b.\r \n" ); document.write( "\n" ); document.write( "55=-1/500 (2000) + b \n" ); document.write( "55 = -4 +b \n" ); document.write( "b=59\r \n" ); document.write( "\n" ); document.write( "EQUATION: price of shirt =(-1/500)(number of shirts) +59\r \n" ); document.write( "\n" ); document.write( "How many can be sold at $50 each?\r \n" ); document.write( "\n" ); document.write( "50=(-1/500)x+59 \n" ); document.write( "-9=-(1/500)x \n" ); document.write( "x=4500 shirts can be sold at $50 each.\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |