document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=422037>Question 422037</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of four numbers is 771. The ratio of the first number to the second number is 2:3. The ratio of the second number to the third number is 5:4. The ratio of the third number to the fourth number is 5:6. What is the second number? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #294621 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=294621\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the 1st number = x<BR>\n" );
document.write( "x + 3x/2 + 3x/2 * 4/5 + 6x/5 * 6/5<BR>\n" );
document.write( "x + 3x/2 + 6x/5 + 36x/25 = 771<BR>\n" );
document.write( "50x+75x+60x+72x=38550 Multiply each side by 50.<BR>\n" );
document.write( "257x=38550<BR>\n" );
document.write( "x=150<BR>\n" );
document.write( "3x/2=225 the 2nd number<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );