document.write( "Question 422024: log 6 +log (x-3)=2 log y
\n" ); document.write( "2y-x=3 \n" ); document.write( "
Algebra.Com's Answer #294615 by edjones(8007)\"\" \"About 
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log 6 +log (x-3)=2 log y
\n" ); document.write( "10^(log 6)*10^(log (x-3))= 10^log y^2
\n" ); document.write( "6(x-3)=y^2
\n" ); document.write( "y^2=6x-18
\n" ); document.write( "2y-x=3
\n" ); document.write( "2y=x+3
\n" ); document.write( "y=(x+3)/2
\n" ); document.write( "(x^2+6x+9)/4=6x-18
\n" ); document.write( "x^2+6x+9=24x-72
\n" ); document.write( "x^2-18x+81=0
\n" ); document.write( "(x-9)^2=0
\n" ); document.write( "x=9
\n" ); document.write( "y=6
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\n" ); document.write( "Ed
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