document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4407>Question 4407</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many Kilograms of water must be added to 20 kilograms of a 10% salt solution to produce a 5% solution ?\r<BR>\n" );
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document.write( "Please help me with not only showing how this is done, but explaining the steps. I am terrible in math!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2946 by </B><A HREF=/tutors/aboutme.mpl?userid=guapa><B>guapa(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=guapa><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2946\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x represent the amount of water to be added.<BR>\n" );
document.write( "You can use the following guideline:<BR>\n" );
document.write( "Amount of water in 10%  + Amount of water added = Amount of water in 5% solution<BR>\n" );
document.write( "      10%(20)           +       0%(x)           =        5%(20+x)<BR>\n" );
document.write( "0.1(20)+ 0 = 0.05(20+x) Now simplify the terms<BR>\n" );
document.write( "2+0=1+0.05x<BR>\n" );
document.write( "2 = 1 + 0.05x Substract 1 from both sides<BR>\n" );
document.write( "2-1 = 1 +0.05x - 1<BR>\n" );
document.write( "1 = 0.05x Divide both sides by 0.05<BR>\n" );
document.write( "1/0.05 = 0.05x/0.05<BR>\n" );
document.write( "x = 20<BR>\n" );
document.write( "So, 20kg water must be added. </SPAN>\n" );
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