document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=421979>Question 421979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me simplify this equation: (4-2i)/(7+3i) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #294591 by </B><A HREF=/tutors/aboutme.mpl?userid=shree840><B>shree840(260)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=shree840><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=shree840><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=294591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (4-2i)(7+3i)\r<BR>\n" );
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document.write( "remember i^2=-1<BR>\n" );
document.write( "use either foil method or break it up<BR>\n" );
document.write( "f first  4*7=28<BR>\n" );
document.write( "o outer  4*3i=12i<BR>\n" );
document.write( "i innner  -2i*7=-14i\r<BR>\n" );
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document.write( "l last    -2i*3i=-6i^2  =-6*-2=12<BR>\n" );
document.write( "28+12i-14i+12<BR>\n" );
document.write( "-2i+40 </SPAN>\n" );
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