document.write( "Question 421877: A man walks for 2 hours - on the way there he walks straight at 4/km per hour and uphill to the point at 3/km per hour. On the way back he walks downhill at 6/km per hour and straight at 4/km per hour. How many kilometers has he travelled in total after 2 hours? \n" ); document.write( "
Algebra.Com's Answer #294568 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A man walks for 2 hours - on the way there he walks straight at 4/km per hour \n" ); document.write( " and uphill to the point at 3/km per hour. \n" ); document.write( "On the way back he walks downhill at 6/km per hour and straight at 4/km per hour. \n" ); document.write( " How many kilometers has he traveled in total after 2 hours? \n" ); document.write( ": \n" ); document.write( "Let f = dist of level ground \n" ); document.write( "Let h = dist of the hill \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = dist/speed \n" ); document.write( ": \n" ); document.write( "lev time + uphill time + downhill time + lev time = 2 hrs \n" ); document.write( " \n" ); document.write( "combine like terms, use common denominator for the hill times \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "; \n" ); document.write( "Multiply by 12, results \n" ); document.write( "3(2f) + 2(3h) = 12(2) \n" ); document.write( "6f + 6h = 24 \n" ); document.write( ": \n" ); document.write( "Simplify, divide by 6 \n" ); document.write( "f + h = 4 km is one way distance \n" ); document.write( "therefore \n" ); document.write( "total dist in 2 hrs = 8 km \n" ); document.write( " \n" ); document.write( " |