document.write( "Question 421877: A man walks for 2 hours - on the way there he walks straight at 4/km per hour and uphill to the point at 3/km per hour. On the way back he walks downhill at 6/km per hour and straight at 4/km per hour. How many kilometers has he travelled in total after 2 hours? \n" ); document.write( "
Algebra.Com's Answer #294568 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A man walks for 2 hours - on the way there he walks straight at 4/km per hour
\n" ); document.write( " and uphill to the point at 3/km per hour.
\n" ); document.write( "On the way back he walks downhill at 6/km per hour and straight at 4/km per hour.
\n" ); document.write( " How many kilometers has he traveled in total after 2 hours?
\n" ); document.write( ":
\n" ); document.write( "Let f = dist of level ground
\n" ); document.write( "Let h = dist of the hill
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: Time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "lev time + uphill time + downhill time + lev time = 2 hrs
\n" ); document.write( "\"f%2F4\" + \"h%2F3\" + \"h%2F6\" + \"f%2F4\" = 2
\n" ); document.write( "combine like terms, use common denominator for the hill times
\n" ); document.write( "\"%282f%29%2F4\" + \"%282h%29%2F6\" + \"h%2F6\" = 2
\n" ); document.write( "\"%282f%29%2F4\" + \"%283h%29%2F6\" = 2
\n" ); document.write( ";
\n" ); document.write( "Multiply by 12, results
\n" ); document.write( "3(2f) + 2(3h) = 12(2)
\n" ); document.write( "6f + 6h = 24
\n" ); document.write( ":
\n" ); document.write( "Simplify, divide by 6
\n" ); document.write( "f + h = 4 km is one way distance
\n" ); document.write( "therefore
\n" ); document.write( "total dist in 2 hrs = 8 km
\n" ); document.write( "
\n" ); document.write( "
\n" );