document.write( "Question 421257: the perimeter is 104 inches. the length exceeds the width by 32 inches. what is the length and width? \n" ); document.write( "

Algebra.Com's Answer #294561 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "the length exceeds the width by 32 inches
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document.write( "Let x and (x+32in) represent the width and length respectively
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document.write( " 104in = 2(x+32in) + 2x
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document.write( " 104in = 2x +64in + 2x
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document.write( " 40in = 4x
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document.write( "  10in = x, the width.  the length is 42in  (10in+32in)
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document.write( "CHECKING our Answer***
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document.write( " 84in + 20in = 104in
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