document.write( "Question 44373: I am having some difficulty with an equation. I worked it out, atleast I thought I did, and I got a totaly different answer then the real answer.\r
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document.write( "4x-3y+7z=38
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document.write( "x+4y+z=16
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document.write( " 5y-z=6\r
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document.write( "my final was x=45, y=-2, z=-21
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document.write( "According to my assignments, it was totaly different.
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document.write( "Can you help me with this equation please. \n" );
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Algebra.Com's Answer #29454 by Earlsdon(6294)![]() ![]() ![]() You can put this solution on YOUR website! Solve the system of equations: \n" ); document.write( "1) \n" ); document.write( "2) \n" ); document.write( "3) \n" ); document.write( "\n" ); document.write( "Rewrite equation 3) as: \n" ); document.write( "3a) \n" ); document.write( "\n" ); document.write( "1a) \n" ); document.write( "2a) \n" ); document.write( "\n" ); document.write( "Simplify 1a) and 2a)\r \n" ); document.write( "\n" ); document.write( "1b) \n" ); document.write( "2b) \n" ); document.write( "\n" ); document.write( "Multiply equation 2b) by 4 and subtract equation 1b) from it.\r \n" ); document.write( "\n" ); document.write( "2b) \n" ); document.write( "1b) - \n" ); document.write( "4) \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Finally, substitute y=2 and z=4 into equation 2 (or into equation 1) and solve for x.\r \n" ); document.write( "\n" ); document.write( "2) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check: Substitute x = 4, y = 2, and z = 4 into the three original equations.\r \n" ); document.write( "\n" ); document.write( "1) \n" ); document.write( "2) \n" ); document.write( "3) \n" ); document.write( " \n" ); document.write( " |