document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=421866>Question 421866</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular block has a square base. The length of each side of the base is (&#8730;3 - &#8730;2)m and volume of the block is (4&#8730;2 - 3&#8730;3) cubic metre. Find the height of the block in the form (a&#8730;2 + b&#8730;3) where a and b are constants.<BR>\n" );
document.write( "*&#8730; = square root or under root :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #294507 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=294507\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> h(sqrt(3)-sqrt(2))^2=4sqrt(2)-3sqrt(3)<BR>\n" );
document.write( "h(5-2sqrt(3)(sqrt(2))=...<BR>\n" );
document.write( "h=(4sqrt(2)-3sqrt(3))/(5-2sqrt(6))<BR>\n" );
document.write( "=(4sqrt(2)-3sqrt(3))/(5-2sqrt(6)) * (5+2sqrt(6))/(5+2sqrt(6)) rationalize the denominator.<BR>\n" );
document.write( "=sqrt(3)+2sqrt(2)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed\r<BR>\n" );
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