document.write( "Question 421697: i need a lot of help with these questions i do not understand them at all..! pleas help.! \r
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document.write( "1.What is the distance between the following points?
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document.write( "(-2 sq root 7,10) (4 sq rt 7,8)
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document.write( "2.What is the axis of symmetry of the parabola with the equation x – 4 = 1/4(y + 1)2
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document.write( "3.Find the foci of an ellipse with the equation 7(x – 2)2 + 3(y – 2)2 = 21.
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document.write( "4.Find the vertices of a hyperbola with the equation (x + 3)2 – 4(y – 2)2 = 4
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document.write( "5.Find the foci of a hyperbola with the equation 9y2 – 72y – 16x2 – 64x – 64 = 0\r
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document.write( "i need the last few to be in (a,b) form.. Thanks.! \n" );
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Algebra.Com's Answer #294496 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! 1.What is the distance between the following points? \n" ); document.write( "(-2 sq root 7,10) (4 sq rt 7,8) \n" ); document.write( "2.What is the axis of symmetry of the parabola with the equation \n" ); document.write( " x – 4 = 1/4(y + 1)2 \n" ); document.write( "3.Find the foci of an ellipse with the equation 7(x – 2)2 + 3(y – 2)2 = 21. \n" ); document.write( "4.Find the vertices of a hyperbola with the equation (x + 3)2 – 4(y – 2)2 = 4 \n" ); document.write( "5.Find the foci of a hyperbola with the equation 9y2 – 72y – 16x2 – 64x – 64 = 0 ..\r \n" ); document.write( "\n" ); document.write( "1.The formula for finding distance between two points: \n" ); document.write( "d=sqrt[(x1-x2)^2+(y1-y2)^2] \n" ); document.write( "for given points, \n" ); document.write( "distance=sqrt[(4sqrt7-(-2sqrt7))^2+(8-10)^2] \n" ); document.write( "=sqrt[(6sqrt7)^2+(-2)^2] \n" ); document.write( "=sqrt[252+4]=sqrt256=16 (ans) \n" ); document.write( ".. \n" ); document.write( "2.x–4=1/4(y+1)2 \n" ); document.write( "This can be rewritten: \n" ); document.write( "x-4=1/2(y+1)^2 \n" ); document.write( "or x=1/2(y+1)^2+4 \n" ); document.write( "This is now written in standard form of a parabola, x=A(y-k)^2+h, with (h,k) being the (x,y) coordinates of the parabola. \n" ); document.write( "For the given equation, this is a parabola that opens sideways to the right, with the vertex at (4,-1). The axis of symmetry is y=-1 \n" ); document.write( "The graph below will help you understand what some of the numbers above represent: \n" ); document.write( ".. \n" ); document.write( "y=-1+-(2x-8)^.5 \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "3. 7(x–2)^2+3(y–2)^2=21 \n" ); document.write( " Standard form for an ellipse:(x-h)^2/a^2+(y-k)^2/b^2 \n" ); document.write( " or(y-k)^2/a^2+(x-h)^2/b^2,a>b \n" ); document.write( " for given equation, divide by 21 to write it in standard form, \n" ); document.write( " (x–2)^2/3+(y–2)^2/7=1 (Since the denominator of the y^2-term is greater than \n" ); document.write( " the denominator of the x^2-term, the given equation is of the second standard \n" ); document.write( " form listed above.) \n" ); document.write( " (y–2)^2/7+(x–2)^2/3=1 \n" ); document.write( " This an ellipse with center at (2,2) with vertical major axis. \n" ); document.write( " a^2=7 \n" ); document.write( " a=sqrt7 \n" ); document.write( " b^2=3 \n" ); document.write( " b=sqrt3 \n" ); document.write( " c^2=a^2-b^2=7-3=4 \n" ); document.write( " c=sqrt4=2 \n" ); document.write( " foci=+-c from the center on the vertical major axis \n" ); document.write( " =(2,4) and (2,0) \n" ); document.write( " The graph of the given ellipse below may help you understand some of the \n" ); document.write( " numbers I came up with: \n" ); document.write( ".. \n" ); document.write( "y=2+-(7-(7/3)(x-2)^2)^.5 \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "4.Find the vertices of a hyperbola with the equation (x+3)^2–4(y–2)^2=4\r \n" ); document.write( "\n" ); document.write( "(x+3)^2–4(y–2)^2=4 \n" ); document.write( "Standard form of a hyperbola: (x-h)^2/a^2-(y-k)^2/b^2=1. Notice this form is almost as same as that of an ellipse except a hyperbola has a negative second term. \n" ); document.write( "Divide given equation by 4, \n" ); document.write( "(x+3)^2/4–(y–2)^2/1=1 \n" ); document.write( "This is a hyperbola with center at (-3,2) and it has a horizontal transverse axis at y=2, that is, it opens sideways. \n" ); document.write( "a^2=4 \n" ); document.write( "a=2 \n" ); document.write( "b^2=1 \n" ); document.write( "b=1 \n" ); document.write( "c^2=a^2+b^2 \n" ); document.write( "c=sqrt(4+1)=sqrt(5)=2.24 \n" ); document.write( "vertices on the transverse axis=-3+-a=(-5,2) and (-1,2) \n" ); document.write( "Foci on the transverse axis=-3+-c=-3+-2.24=(-5.24,2) and (.76,2) \n" ); document.write( "The graph of the given hyperbola below could serve as a check on some of the numbers like the center, vertices and foci. \n" ); document.write( ".. \n" ); document.write( "y=2+-((x+3)^2/4-1)^.5 \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( "5.Find the foci of a hyperbola with the equation 9y2–72y–16x2–64x–64=0 \n" ); document.write( "9y2–72y–16x2–64x–64=0 \n" ); document.write( "you need to complete the square before you can see it in standard form:\r \n" ); document.write( "\n" ); document.write( "9(y2–8y+16)–16(x2+4x+4)=64+144-64=144 \n" ); document.write( "9(y-4)^2-16(x+2)^2=144 \n" ); document.write( "Divide by 144 \n" ); document.write( "(y-4)^2/16-(x+2)^2/9=1 \n" ); document.write( "This is a hyperbola with center at (-2,4) with a vertical transverse axis,x=-2, that is it opens up and down. \n" ); document.write( "a^2=16 \n" ); document.write( "a=4 \n" ); document.write( "b^2=9 \n" ); document.write( "b=3 \n" ); document.write( "c=sqrt(a^2+b^2)=sqrt(25)=5 \n" ); document.write( "On the vertical transverse axis, \n" ); document.write( "foci:(-2,4+-c)=(-2,4+-5)=(-2,9) and (-2,-1) \n" ); document.write( "The graph below can serve as a check on the center and foci.\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "y=4+-(16(1+(x+2)^2/9))^.5 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |