document.write( "Question 421770: a certain aircraft can fly 1600 miles with the wind in 5 hours and travel the same distance against the wind in 8 hours. What is the spee=d of the wind and the speed of the plane in still air? ( set two equations up ex. y=2x+3 and x=2y+10 and solve using substitution method or addition method) \n" ); document.write( "
Algebra.Com's Answer #294457 by mananth(16946)![]() ![]() You can put this solution on YOUR website! against wind 8 hours \n" ); document.write( "with wind 5 hours \n" ); document.write( " \n" ); document.write( "Distance = same= 1600 \n" ); document.write( "plane speed =x \n" ); document.write( "wind speed =y \n" ); document.write( "t=d/r \n" ); document.write( "1600/(x-y)=8.00 \n" ); document.write( "8(x-y)= 1,600.00 \n" ); document.write( "8x-8y=1600 ....................1 \n" ); document.write( "1600/ ( x + y )= 5 \n" ); document.write( "5 ( x + y ) = 1600 \n" ); document.write( "5 x + 5 y = 1600 ...............2 \n" ); document.write( "Multiply (1) by 5 \n" ); document.write( "Multiply (2) by 8 \n" ); document.write( "we get \n" ); document.write( "40 x + -40 y = 8000 \n" ); document.write( "40 x + 40 y = 12800 \n" ); document.write( "80 x = 20800 \n" ); document.write( "/80 \n" ); document.write( "x=260 mph plane speed \n" ); document.write( " \n" ); document.write( "plug value of x in (1) \n" ); document.write( "8x-8y=1600 \n" ); document.write( "2080-8y= 1600 \n" ); document.write( "-8y=1600 -2080 \n" ); document.write( "-8y=-480 \n" ); document.write( "y=60mph wind speed \n" ); document.write( " \n" ); document.write( " |