document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=421777>Question 421777</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A right triangle has one leg measuring \"x\" inches and second leg measuring (2x+2)inches. The hypotenuse measures (2x+3) inches long. Find the length of all three sides. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #294456 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=294456\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> using the pythagoras theorem\r<BR>\n" );
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document.write( "x^2+(2x+2)^2=(2x+3)^2\r<BR>\n" );
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document.write( "x^2+4x^2+8x+4=4x^2+12x+9<BR>\n" );
document.write( "x^2-4x-5=0<BR>\n" );
document.write( "x^2-5x+x-5=0<BR>\n" );
document.write( "x(x-5)+1(x-5)=0<BR>\n" );
document.write( "(x-5)(x+1)=0<BR>\n" );
document.write( "x= 5 \r<BR>\n" );
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document.write( "The sides are<BR>\n" );
document.write( "one leg  5 in\r<BR>\n" );
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document.write( "second (2x+2)===>12 in<BR>\n" );
document.write( "hypotenuse (2x+3)===>13 in<BR>\n" );
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