document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44549>Question 44549</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need some help with a negative coefficient.<BR>\n" );
document.write( "I need to multiply the following equations.<BR>\n" );
document.write( "4x-36/x^2+x multiplied by 3x/9-x<BR>\n" );
document.write( "This is what I have come up with so far: factoring out the equations I get 4(x-9)/x(x+1)multiplied by 3x/9-x.  I can cancel out one x and I can also cancel out the 9-x and the x-9 which will give me a -1.  This leaves me with the following equation<BR>\n" );
document.write( "12/-1(x+1) which equals 12/-x-1.  My question is this: what do I do with the negative coefficient? do I multipy by a -1?  and would this give me -12/x+1 or 12/x+1.\r<BR>\n" );
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document.write( "thank you for the assistance!<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29445 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29445\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Will give you -12/(x+1)\r<BR>\n" );
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document.write( "The rule is as follows:<BR>\n" );
document.write( "Every fraction has three signs:<BR>\n" );
document.write( "sign of the fraction<BR>\n" );
document.write( "sign of the numerator<BR>\n" );
document.write( "sign of the denominator\r<BR>\n" );
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document.write( "You may change any two of these signs and still<BR>\n" );
document.write( "have the original fraction.\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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