document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=421710>Question 421710</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am not sure if this is the area to do this question in but here goes. I am doing a practice final, and this question has me stumped.\r<BR>\n" );
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document.write( "The owner of a rectangular swimming pool, with dimensions 10 meters by 25 meters, wants to surround the pool with a concrete border of uniform width. The owner has enough concrete mix to cover 74 square meters. How wide should the border be?\r<BR>\n" );
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document.write( "I need the equation from beginning to end. So far I have \r<BR>\n" );
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document.write( "(2l+25)(2w+10)-250=74<BR>\n" );
document.write( "(50l)(20w)\r<BR>\n" );
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document.write( "My original answer was 4 meters wide but that's wrong, I already know that the answer needs to be 2 meters wide but I can't figure out the equation to get me to the correct answer.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #294428 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=294428\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> he owner of a rectangular swimming pool, with dimensions 10 meters by 25 meters, wants to surround the pool with a concrete border of uniform width. The owner has enough concrete mix to cover 74 square meters. How wide should the border be? <BR>\n" );
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document.write( "Let x = the width of the concrete border<BR>\n" );
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document.write( "The the overall dimensions will be (2x+10) by (2x+25)<BR>\n" );
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document.write( "overall area - pool area = 74 sq/m<BR>\n" );
document.write( "(2x+10)(2x+25) - 250 = 74; (which essentially, is what you have)<BR>\n" );
document.write( "FOIL<BR>\n" );
document.write( "(4x^2 + 50x + 20x + 250) - 250 = 74<BR>\n" );
document.write( "4x^2 + 70x - 74 = 0<BR>\n" );
document.write( "Simplify, divide by 2<BR>\n" );
document.write( "2x^2 + 35x - 37 = 0<BR>\n" );
document.write( "Factors to<BR>\n" );
document.write( "(2x + 37)(x - 1) = 0<BR>\n" );
document.write( "Positive solution<BR>\n" );
document.write( "x = 1 meter wide<BR>\n" );
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document.write( "You said it should be 2, check this by finding the overall area, subtract this pool area:<BR>\n" );
document.write( "(2(1) + 10)(2(1) + 25) - 250 = <BR>\n" );
document.write( "(2+10)(2+25) - 250 =<BR>\n" );
document.write( "(12 * 27) - 250 <BR>\n" );
document.write( "324 - 250 = 74, confirms our answer of x = 1<BR>\n" );
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