document.write( "Question 421542: Can you please assist with this problem. I am unsure if I have the correct answer?\r
\n" ); document.write( "\n" ); document.write( "The owner of an appliance store uses a normal distribution with mean 10 and variance 9 to model the weekly net sales (in units of $1000). The owner needs $3500 a week to pay his staff. Determine the probability that the weekly net sales will not be enough to pay the whole of this amount.\r
\n" ); document.write( "\n" ); document.write( "Thank you so much!
\n" ); document.write( "

Algebra.Com's Answer #294395 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The owner of an appliance store uses a normal distribution with mean 10 and variance 9 to model the weekly net sales (in units of $1000). The owner needs $3500 a week to pay his staff. Determine the probability that the weekly net sales will not be enough to pay the whole of this amount.
\n" ); document.write( "-------
\n" ); document.write( "z(3500) = (3.5-10)/9 = -0.7778
\n" ); document.write( "-----
\n" ); document.write( "P(x < 3.5 thousand) = P(z < -0.7778) = 0.2184
\n" ); document.write( "-----
\n" ); document.write( "============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "============
\n" ); document.write( "
\n" ); document.write( "
\n" );