document.write( "Question 421513: A father is five times as old as his daughter. In six years he will be three times as old as she will be. How old is the daughter now. ( i know how to solve the problem, i am just stuck with assigning the formulas. In my math class its asked that we assign each person a variable ie: x and the other x+2) Any help would be great thanks. \n" ); document.write( "
Algebra.Com's Answer #294387 by josmiceli(19441)\"\" \"About 
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Let \"x\" = Father's age now
\n" ); document.write( "Let \"y\" = Daughter's age now
\n" ); document.write( "given:
\n" ); document.write( "(1) \"+x+=+5y+\"
\n" ); document.write( "(2) \"x+%2B+6+=++3%2A%28y+%2B+6%29+\"
\n" ); document.write( "-------------------
\n" ); document.write( "There are 2 equations and 2 unknowns, so it's solvable
\n" ); document.write( "By substitution:
\n" ); document.write( "(2) \"5y+%2B+6+=++3%2A%28y+%2B+6%29+\"
\n" ); document.write( "(2) \"5y+%2B+6+=+3y+%2B+18+\"
\n" ); document.write( "(2) \"2y+%2B+6+=+18+\"
\n" ); document.write( "(2) \"2y+=+12\"
\n" ); document.write( "\"y+=+6\"
\n" ); document.write( "and
\n" ); document.write( "(1) \"x+=+5y\"
\n" ); document.write( "\"x+=+30\"
\n" ); document.write( "The Father is 30 and the daughter is 6\r
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