document.write( "Question 44546: elimination method\r
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document.write( "3(a-b)=15
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document.write( "4a=b+1 \n" );
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Algebra.Com's Answer #29433 by Nate(3500) ![]() You can put this solution on YOUR website! 3(a - b) = 15 \n" ); document.write( "3a - 3b = 15 \n" ); document.write( "+ \n" ); document.write( "4a = b + 1 \n" ); document.write( "4a - b = 1 \n" ); document.write( "-12a + 3b = -3 \n" ); document.write( "= \n" ); document.write( "-9a = 12 \n" ); document.write( "a = -4/3 \n" ); document.write( "so: \n" ); document.write( "4a = b + 1 \n" ); document.write( "4(-4/3) = b + 1 \n" ); document.write( "(-16/3) = b + 1 \n" ); document.write( "(-19/3) = b \n" ); document.write( "Check: \n" ); document.write( "'a' are x-values \n" ); document.write( "'b' are y-values \n" ); document.write( "Answer: (-1 1/3, -6 1/3) \n" ); document.write( " |