document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44539>Question 44539</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/061822176x/algebrahomeworkh>Elemetary Geometry for college students</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> The problem consist of a diagram: A is parallel to B and C is parallel to D (A and B are horizontal line; C and D are vertical lines both with slight slant). The angles are numbered as follows (starting from top):On line A is <BR>\n" );
document.write( "                                            1 2   3 4<BR>\n" );
document.write( "                                           5 6   7 8\r<BR>\n" );
document.write( "\n" );
document.write( "                           On Line B:<BR>\n" );
document.write( "                                       9 10   11 12<BR>\n" );
document.write( "                                     13 14   15 16<BR>\n" );
document.write( "Given: m<9= 2x+17; m<11= 5x-94 <BR>\n" );
document.write( "Find: x<BR>\n" );
document.write( "What I have tried is taking m<9 =m<11 so 2x+17=5x-94 then I took the 2x+17 and moved it to the other side: 5x-94+2x+17=0 simply 7x-77=0. I think this maybe where I'm making a mistake. Can you Help me solve this equation to find x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29423 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29423\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE PROBLEM IS NOT CLEAR..PLEASE MAKE A SKETCH<BR>\n" );
document.write( "Given: m<9= 2x+17; m<11= 5x-94<BR>\n" );
document.write( "I TAKE IT YOU MEAN<BR>\n" );
document.write( "2X+7=M<9........................I<BR>\n" );
document.write( "5X-94=M<11.................II<BR>\n" );
document.write( "THEN EQN.I HOLDS,AS IF M<9 ,IT IS OBVIOUSLY<11<BR>\n" );
document.write( "SO THE SOLUTION SATISFYING BOTH IS <BR>\n" );
document.write( "2X+7<9<BR>\n" );
document.write( "2X<9-7=2<BR>\n" );
document.write( "X<1 IS THE ANSWER\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Find: x<BR>\n" );
document.write( "What I have tried is taking m<9 =m<11 so 2x+17=5x-94 then I took the 2x+17 and moved it to the other side: 5x-94+2x+17=0 simply 7x-77=0. I think this maybe where I'm making a mistake. Can you Help me solve this equation to find x? </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );