document.write( "Question 421167: verify each of the following identities.
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document.write( " pls. help me solve this problem.. thank you in advance\r
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document.write( "1. 1+cos theta=(tan^2theta)/(1-sec theta + tan^2theta)
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document.write( "2. cos 3x = cos^3x-3sin^2x cos x \n" );
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Algebra.Com's Answer #294223 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! 1. 1+cos theta=(tan^2theta)/(1-sec theta + tan^2theta) \n" ); document.write( " 2. cos 3x = cos^3x-3sin^2x cos x\r \n" ); document.write( "\n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( "1.1+cos=tan^2/1-sec+tan^2 \n" ); document.write( "Starting with right-hand side, \n" ); document.write( "tan^2/1-sec+tan^2 \n" ); document.write( "using identity:(tan^2x+1=sec^2x) \n" ); document.write( "sec^2-1/1-sec+sec^2-1 \n" ); document.write( "=(sec+1)(sec-1)/sec^2-sec \n" ); document.write( "=(sec+1)(sec-1)/sec(sec-1) \n" ); document.write( "=(sec+1)/sec \n" ); document.write( "=(sec/sec)+(1/sec) \n" ); document.write( "=1+cos \n" ); document.write( "verified: \n" ); document.write( "left-hand side = right hand side \n" ); document.write( ".. \n" ); document.write( "2.cos3x=cos^3x-3sin^2xcosx \n" ); document.write( "Starting with left-hand side \n" ); document.write( "Using identity:(cos(x+y)=cosxcosy-sinxsiny) \n" ); document.write( "cos3x=cos(x+2x)=cosxcos2x-sinxsin2x \n" ); document.write( "Using identities:(Cos2x and sin2x) \n" ); document.write( "=cosx(cos^2x-sin^2x)-sinx(2sinxcosx) \n" ); document.write( "=cos^3x-sin^2xcosx-2sin^2cosx \n" ); document.write( "=cos^3x-3sin^2cosx \n" ); document.write( "verified: \n" ); document.write( "left-hand side=right-hand side \n" ); document.write( " \n" ); document.write( " |