document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=421204>Question 421204</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PLEASE HELP<BR>\n" );
document.write( "Find the area of the region limited by the curve y=(x+2)*(3x-3) and the axis x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #294178 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=294178\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Solve:\r<BR>\n" );
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document.write( "       <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=int%283x%5E2%2Cdx%2C+-2%2C+1%29%2Bint%283x%2Cdx%2C+-2%2C+1%29-int%28+6%2Cdx%2C+-2%2C+1%29 ALIGN=MIDDLE  ALT=\"int%283x%5E2%2Cdx%2C+-2%2C+1%29%2Bint%283x%2Cdx%2C+-2%2C+1%29-int%28+6%2Cdx%2C+-2%2C+1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  \r<BR>\n" );
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document.write( "       <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+3%2Aint%28x%5E2%2Cdx%2C+-2%2C+1%29%2B3%2Aint%28x%2Cdx%2C-2%2C+1%29-int%286%2Cdx%2C+-2%2C+1%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "        (x^3+(3/2)x^2- 6x)|(-2, 1)=[1^3+3/2*1^2-6*1 ]-[(-2)^3+3/2*  \r<BR>\n" );
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document.write( "        (-2)^2-6(-2)]=25/2 \r<BR>\n" );
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document.write( " Answer: The area under the curve is 25/2 square units. \r<BR>\n" );
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