document.write( "Question 421146: A set of 50 data values has a mean of 39 and a variance of 9.
\n" );
document.write( "I. Find the standard score (z) for a data value = 43.
\n" );
document.write( "II. Find the probability of a data value < 43. \n" );
document.write( "
Algebra.Com's Answer #294159 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A set of 50 data values has a mean of 39 and a variance of 9. \n" ); document.write( "Note: standard deviation = sqrt(9) = 3 \n" ); document.write( "-------------------- \n" ); document.write( "I. Find the standard score (z) for a data value = 43. \n" ); document.write( "--- \n" ); document.write( "z(43) = (43-39)/3 = 4/3 \n" ); document.write( "------------------------------ \n" ); document.write( "II. Find the probability of a data value < 43. \n" ); document.write( "P(x < 43) = P(z < 4/3) = normalcdf(-100,43) = 0.9088 \n" ); document.write( "====================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "====== \n" ); document.write( " \n" ); document.write( " |