document.write( "Question 421152: a merchant wants to mix peanuts worth $3 per pound with jelly beans worth $1.50 per pound to make 30 pounds of mixture worth $2.10 per pound. how many pounds of each should be used? \n" ); document.write( "
Algebra.Com's Answer #294138 by ptaylor(2198)\"\" \"About 
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Let x=amount of jelly beans needed
\n" ); document.write( "Then 30-x=amount of peanuts needed
\n" ); document.write( "Now we know that the total value of the peanuts and jelly beans before the mixture takes place has to equal the value of the final mixture.\r
\n" ); document.write( "\n" ); document.write( "Value of peanuts and jelly beans before the mixture takes place ($ understood):
\n" ); document.write( "1.50x+3(30-x)
\n" ); document.write( "Value of the final mixture:
\n" ); document.write( "2.10*30\r
\n" ); document.write( "\n" ); document.write( "So our equation to solve is:
\n" ); document.write( "1.50x+3(30-x)=2.10*30 simplify
\n" ); document.write( "1.50x+90-3x=63 subtract 90 from each side and collect like terms
\n" ); document.write( "-1.50x=-27
\n" ); document.write( "x=18 lb----------------amount of jelly beans needed
\n" ); document.write( "30-x=30-18=12 lb---------------amount of peanuts needed
\n" ); document.write( "CK
\n" ); document.write( "18*1.50+12*3=2.10*30
\n" ); document.write( "27+36=63
\n" ); document.write( "63=63\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r
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