document.write( "Question 421139: b) Length of a rectangle is 3 more than its width. The perimeter of the rectangle is 30. Find the length and width.
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #294132 by algebrahouse.com(1659)\"\" \"About 
You can put this solution on YOUR website!
\"b) Length of a rectangle is 3 more than its width. The perimeter of the rectangle is 30. Find the length and width.\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = width
\n" ); document.write( "x + 3 = length {length is 3 more than width}\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Perimeter of a rectangle = 2(width) + 2(length}\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2x + 2(x + 3) = 30 {perimeter is 2(width) + 2(length)}
\n" ); document.write( "2x + 2x + 6 = 30 {used distributive property}
\n" ); document.write( "4x + 6 = 30 {combined like terms}
\n" ); document.write( "4x = 24 {subtracted 6 from both sides}
\n" ); document.write( "x = 6 {divided both sides by 4}
\n" ); document.write( "x + 3 = 9 {substituted 6, in for x, into x + 3}\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "width = 6 and length = 9
\n" ); document.write( "www.algebrahouse.com \n" ); document.write( "
\n" );