document.write( "Question 421091: barry is 8 years older than his sister. in 3 years he will be twice as old as sue was 5 years ago. find their ages now. \n" ); document.write( "
Algebra.Com's Answer #294127 by algebrahouse.com(1659)\"\" \"About 
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\"barry is 8 years older than his sister. in 3 years he will be twice as old as sue was 5 years ago. find their ages now.\"\r
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\n" ); document.write( "\n" ); document.write( "x = sister's age now
\n" ); document.write( "x + 8 = Barry's age now\r
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\n" ); document.write( "\n" ); document.write( "x + 3 = sister in 3 years
\n" ); document.write( "x + 11 = Barry in 3 years\r
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\n" ); document.write( "\n" ); document.write( "x + 11 = 2(x - 5) {in 3 years, he will be twice as old as her, 5 yrs ago}
\n" ); document.write( "x + 11 = 2x - 10 {used distributive property}
\n" ); document.write( "11 = x - 10 {subtracted x from both sides}
\n" ); document.write( "x = 21 {added 10 to both sides}
\n" ); document.write( "x + 8 = 29 {substituted 21, in for x, into x + 8}\r
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\n" ); document.write( "\n" ); document.write( "Barry is 29 and Sue is 21
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