document.write( "Question 44516This question is from textbook INTERMEDIATE ALGEBRA
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document.write( ": Solve by completing the square:
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document.write( "x2 + 6x + 4 = 0 \n" );
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Algebra.Com's Answer #29412 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! x2 + 6x + 4-4 = 0-4 \n" ); document.write( "x^2 + 6x +(6/2)^2 = -4+(6/2)^2 \n" ); document.write( "x^2 + 6x +(3)^2 = -4+(3)^2 \n" ); document.write( "(x+3)(x+3)= -4+9 \n" ); document.write( "(x+3)^2= 5 \n" ); document.write( "sqrt[(x+3)^2]= sqrt[5] \n" ); document.write( "x+3=sqrt[5] \n" ); document.write( "x+3-3=-3+sqrt[5] \n" ); document.write( "Answer: x=-3 + sqrt[5] \n" ); document.write( " \n" ); document.write( " |