document.write( "Question 44523: There is one more that I can't get.\r
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document.write( "Roll a pair of dice 20 times and count the number of times you get a 7 and the number of times you get an 9. \r
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document.write( "I did this but I can't figure out the following: \r
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document.write( "a. Compute Pe(7)
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document.write( "b Compute Pe(8)
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document.write( "c Compute Pe (7 or 8)
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document.write( "d Compute Pe (7) + pe (8)
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document.write( "e Explain why the results of parts c and d are as they are. \n" );
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Algebra.Com's Answer #29411 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! There is one more that I can't get. \n" ); document.write( "Roll a pair of dice \n" ); document.write( "THERE ARE 6 POSSIBILITIES ON ONE DICE AND ANOTHER 6 ON THE SECOND DICE \n" ); document.write( "HENCE TOTAL NUMBER OF POSSIBILITIES=6*6=36 \n" ); document.write( "WE CAN GET 7 IN THE FOLLOWING WAYS \n" ); document.write( "1+6,2+5,3+4,4+3,5+2,6+1....TOTAL..6 WAYS \n" ); document.write( "HENCE P7=6/36=1/6 \n" ); document.write( "SIMILARLY FOR 9 \n" ); document.write( "3+6,4+5,5+4,6+3.....3 WAYS \n" ); document.write( "P9=3/36=1/12 \n" ); document.write( " 20 times and count the number of times you get a 7 and the number of times you get an 9.....HENCE WE EXPECT THAT IN 20 TRIALS... \n" ); document.write( "7 TO TURN UP IN 20*1/6 TIMES=3 TO 4 TIMES TIMES \n" ); document.write( "9 TO TURN UP IN 20*1/12 TIMES =1 TO 2 TIMES \n" ); document.write( "8 TO TURN UP IN [2+6,3+5,4+4,5+3,6+2=5 WAYS]20*5/36=2 TO 3 TIMES \n" ); document.write( "I did this but I can't figure out the following: \n" ); document.write( "a. Compute Pe(7)=20*1/6 \n" ); document.write( "b Compute Pe(8)=20*5/36 \n" ); document.write( "c Compute Pe (7 or 8)20*{1/6 +5/36}=20*11/36 \n" ); document.write( "d Compute Pe (7) + pe (8)20*11/36 \n" ); document.write( "e Explain why the results of parts c and d are as they are. \n" ); document.write( "OR IS INCLUSIVE OR EITHER 7 OR 8 OR BOTH \n" ); document.write( " |