document.write( "Question 421066: the sum of two numbers is 16, and the difference is 6, what is their product? cannot be 60 \n" ); document.write( "
Algebra.Com's Answer #294056 by richard1234(7193)\"\" \"About 
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We have \"a%2Bb+=+16\" and \"a-b+=+6\". There are two solutions:\r
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\n" ); document.write( "\n" ); document.write( "Solution 1:
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\n" ); document.write( "We can solve the system by adding both equations to produce \"2a+=+22\" --> \"a+=+11\". Replace a with 11 in either equation to get \"b+=+5\", \"ab+=+55\".\r
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\n" ); document.write( "\n" ); document.write( "Solution 2:
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\n" ); document.write( "We can square both equations to obtain
\n" ); document.write( "\"a%5E2+%2B+2ab+%2B+b%5E2+=+256\"
\n" ); document.write( "\"a%5E2+-+2ab+%2B+b%5E2+=+36\"\r
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\n" ); document.write( "\n" ); document.write( "Subtracting the second equation from the first, we obtain \"4ab+=+220\" which implies \"ab+=+55\".
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