document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=420953>Question 420953</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a perimeter of 71 feet.  What length and width should it have so that its area is a maximum? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #294018 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=294018\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Denote x ft the length than the width is (71/2)-x and its area is x((71/2)-x).\r<BR>\n" );
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document.write( "  A(x)=-x^2+35.5x Area function is a downward parabola. The maximum value is the  y value of its vertex. x= -b/2a=35.5/2 and y=-(35.5/2)^2+35.5(35.5/2)=315 ft. ( The solution (0,0) is rejected from our real problem)\r<BR>\n" );
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document.write( "Answer: The maximum area is approximately 315 square feet.\r<BR>\n" );
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