document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=420900>Question 420900</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many 4 person committees are possible from a group of 12 people<BR>\n" );
document.write( "a. there are no restrictions<BR>\n" );
document.write( "b. both jim and mary must be on the committee<BR>\n" );
document.write( "c. either jim or mary (not both) must be on the committee </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #294011 by </B><A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><B>sudhanshu_kmr(1152)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sudhanshu_kmr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sudhanshu_kmr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=294011\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "a. there are no restrictions\r<BR>\n" );
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document.write( "no. of ways = 12C4  = 495\r<BR>\n" );
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document.write( "b. both jim and mary must be on the committee\r<BR>\n" );
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document.write( "no.of ways = 10C2 = 45\r<BR>\n" );
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document.write( "c. either jim or mary (not both) must be on the committee\r<BR>\n" );
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document.write( "no. of ways when jim on the committee but mary not = 10C3 = 120\r<BR>\n" );
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document.write( "no. of ways when mary on the committe but jim not = 10C3 = 120\r<BR>\n" );
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document.write( "total ways = 120+120 = 240\r<BR>\n" );
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document.write( " </SPAN>\n" );
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