document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5719>Question 5719</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A triangular region of the community college parking lot was measured. The measure of the first angle of this triangle is triple the measure of the second angle. The measure of the third angle is 6 degrees less than double the measures of the second angle. What are the measurements of all three angles?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2940 by </B><A HREF=/tutors/aboutme.mpl?userid=arunpaul><B>arunpaul(104)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=arunpaul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2940\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the angles of a triangle be A,B,C<BR>\n" );
document.write( "A = 3B<BR>\n" );
document.write( "C=2B-6<BR>\n" );
document.write( "again we know A+B+C=180 degree<BR>\n" );
document.write( "substituting the value of A and C in the abve equation we have<BR>\n" );
document.write( "3B +B +2B-6 =180<BR>\n" );
document.write( "or 6B = 180+6= 186<BR>\n" );
document.write( "or B = 186/6 =31<BR>\n" );
document.write( "so A = 3B = 3*31= 93 degree<BR>\n" );
document.write( "C = 2B-6 = 2*31-6 = 62-6=56\r<BR>\n" );
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document.write( "so A = 93 degree<BR>\n" );
document.write( "B = 31 degree<BR>\n" );
document.write( "C = 56 degree\r<BR>\n" );
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document.write( "Ans<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );