document.write( "Question 888: The area of a rectangle is x^2-6x+58. Find x if the area of the rectangle is 50 square units. \n" ); document.write( "
Algebra.Com's Answer #294 by usyim88hk(158)![]() ![]() ![]() You can put this solution on YOUR website! x^2-6x+58 = 50 (because they are both the area of the rectangle) \n" ); document.write( " -50 -50 (subtract 50 from both sides) \n" ); document.write( "x^2-6x+8 = 0 (Factor it!!!) \n" ); document.write( "(x-2)(x-4)= 0 (Find x!!!) \n" ); document.write( " x = 2 or 4 \n" ); document.write( "----------------------------------------------------------------------- \n" ); document.write( "Check: \n" ); document.write( "if x=2 \n" ); document.write( "2^2-6(2)+58 = 50 \n" ); document.write( "4-12+58 = 50 \n" ); document.write( "50 = 50 (Correct!) \n" ); document.write( "if x=4 \n" ); document.write( "4^2-6(4)+58 = 50 \n" ); document.write( "8-16+58 = 50 \n" ); document.write( "50 = 50 (Correct!) \n" ); document.write( " |