document.write( "Question 888: The area of a rectangle is x^2-6x+58. Find x if the area of the rectangle is 50 square units. \n" ); document.write( "
Algebra.Com's Answer #294 by usyim88hk(158)\"\" \"About 
You can put this solution on YOUR website!
x^2-6x+58 = 50 (because they are both the area of the rectangle)
\n" ); document.write( " -50 -50 (subtract 50 from both sides)
\n" ); document.write( "x^2-6x+8 = 0 (Factor it!!!)
\n" ); document.write( "(x-2)(x-4)= 0 (Find x!!!)
\n" ); document.write( " x = 2 or 4
\n" ); document.write( "-----------------------------------------------------------------------
\n" ); document.write( "Check:
\n" ); document.write( "if x=2
\n" ); document.write( "2^2-6(2)+58 = 50
\n" ); document.write( "4-12+58 = 50
\n" ); document.write( "50 = 50 (Correct!)
\n" ); document.write( "if x=4
\n" ); document.write( "4^2-6(4)+58 = 50
\n" ); document.write( "8-16+58 = 50
\n" ); document.write( "50 = 50 (Correct!)
\n" ); document.write( "
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