document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=420919>Question 420919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use an inequality to slove the problem<BR>\n" );
document.write( "One side of a triangle is 4 cm shorter than the base, x. The other side is 6 cm longer than the base. What lengths of the base will allow the perimeter of the triangle to be at least 29 cm?<BR>\n" );
document.write( "x=base lenght<BR>\n" );
document.write( "x-4 1st side<BR>\n" );
document.write( "x+6 2nd side<BR>\n" );
document.write( "a+b+c=P<BR>\n" );
document.write( "x+x-4+x+8>or equal to 29             do not know how to make the greater than<BR>\n" );
document.write( "                                     or equal to sign on comp. Lost after that.<BR>\n" );
document.write( "                                     so far is that right, and how do I finish </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293990 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293990\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "Like Livingstone said to Stanley, \"Safari, so goodie\"\r<BR>\n" );
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document.write( "Seriously though, except for one little typo, you have done everything correctly.  The last step you show should look like:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x\ +\ x\ -\ 4\ +\ x\ +\ 6\ \geq\ 29\">\r<BR>\n" );
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document.write( "(6 instead of 8)\r<BR>\n" );
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document.write( "Then it is exactly like solving the analogous equation (except that if you ever have to multiply by a negative, you have to reverse the sense of the inequality sign, greater than becomes less than or vice versa).\r<BR>\n" );
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document.write( "Collect terms:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ 3x\ +\ 2\ \geq\ 29\">\r<BR>\n" );
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document.write( "Add -2 to both sides:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ 3x\ \geq\ 27\">\r<BR>\n" );
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document.write( "Multiply by <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \frac{1}{3}\">:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE \ \ \ \ \ \ \ \ \ \ x\ \geq\ 9\">\r<BR>\n" );
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document.write( "By the way, if you need to render <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \geq\"> or <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \leq\"> in plain text use >= or <=.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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