document.write( "Question 420918: trains A & B are traveling in the same direction on parellel tracks. train a is traveling at 40 miles per hour and train b is traveling at 60 miles per hour. Trai na passes the station at 3:10am. If train b passes the same station at 3:22am, at what time will train b catch up to train a. \n" ); document.write( "
Algebra.Com's Answer #293989 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Start a stopwatch when train B leaves station at 3:22 \n" ); document.write( "How much of a head start does train A have? \n" ); document.write( "Train A left 12 minutes earlier at 3:10, and at 40 mi/hr \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Both trains will now run for the same amount of time, \n" ); document.write( "but A has less distance to travel. \n" ); document.write( "Let \n" ); document.write( "------------------ \n" ); document.write( "Train A: \n" ); document.write( "(1) \n" ); document.write( "Train B: \n" ); document.write( "(2) \n" ); document.write( "------------- \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "This is 24 minutes after the stopwatch started at 3:22, \n" ); document.write( "so B catches A at 3:46 AM \n" ); document.write( " |