document.write( "Question 420918: trains A & B are traveling in the same direction on parellel tracks. train a is traveling at 40 miles per hour and train b is traveling at 60 miles per hour. Trai na passes the station at 3:10am. If train b passes the same station at 3:22am, at what time will train b catch up to train a. \n" ); document.write( "
Algebra.Com's Answer #293989 by josmiceli(19441)\"\" \"About 
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Start a stopwatch when train B leaves station at 3:22
\n" ); document.write( "How much of a head start does train A have?
\n" ); document.write( "Train A left 12 minutes earlier at 3:10, and at 40 mi/hr
\n" ); document.write( "\"d+=+40%2A%2812%2F60%29\"
\n" ); document.write( "\"d+=+40%2F5\"
\n" ); document.write( "\"d+=+8\" mi is A's head start
\n" ); document.write( "Both trains will now run for the same amount of time,
\n" ); document.write( "but A has less distance to travel.
\n" ); document.write( "Let \"d\" = distance from station to where they meet
\n" ); document.write( "------------------
\n" ); document.write( "Train A:
\n" ); document.write( "(1) \"+d+-+8+=+40%2At+\"
\n" ); document.write( "Train B:
\n" ); document.write( "(2) \"d+=+60%2At+\"
\n" ); document.write( "-------------
\n" ); document.write( "(1) \"+d+=+40t+%2B+8+\"
\n" ); document.write( "(2) \"+d+=+60t+\"
\n" ); document.write( "\"+40t+%2B+8+=+60t+\"
\n" ); document.write( "\"+20t+=+8+\"
\n" ); document.write( "\"+t+=+2%2F5+\" hrs
\n" ); document.write( "\"t+=+%282%2F5%29%2A60\" min
\n" ); document.write( "\"+t+=+24+\" min
\n" ); document.write( "This is 24 minutes after the stopwatch started at 3:22,
\n" ); document.write( "so B catches A at 3:46 AM
\n" ); document.write( "
\n" );