document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=420867>Question 420867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If I have a 20 qt radiator containing a 80% antifreeze solution. How much of the solution should I drain and replace with pure water to get a solution that is 50% antifreeze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293968 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293968\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let 82% solution required be x\r<BR>\n" );
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document.write( "percent	----------------	quantity<BR>\n" );
document.write( "82	----------------	x<BR>\n" );
document.write( "water 0%	----------------	20-x<BR>\n" );
document.write( "50.00%	----------------	20		<BR>\n" );
document.write( "...<BR>\n" );
document.write( "82x+0(20	-x)=50*20<BR>\n" );
document.write( "82x=1000		<BR>\n" );
document.write( "/	82	 							<BR>\n" );
document.write( "x=12.2	qt. of82.00%		<BR>\n" );
document.write( "Balance 7.8 qt of water.\r<BR>\n" );
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document.write( "7.8 qt. of 82% will have to be drained and replaced with water			<BR>\n" );
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