document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=420807>Question 420807</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A sphere has a volume of 32 in. If the diameter is halved, find the new volume. help..!!!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293918 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A sphere has a volume of 32 in^3. If the diameter is halved, find the new volume.<BR>\n" );
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document.write( "Vol = (4/3)pi*r^3<BR>\n" );
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document.write( "32 = (4/3)pi*r^3<BR>\n" );
document.write( "24 = pi*r^3<BR>\n" );
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document.write( "r = (24/pi)^(1/3)<BR>\n" );
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document.write( "If the diameter is halved, the radius is halved<BR>\n" );
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document.write( "New radius = (1/2)(24/pi)^(1/3)<BR>\n" );
document.write( "New radius = (1/8)^(1/3)*(24/pi)^(1/3)<BR>\n" );
document.write( "New radius = (3/pi)^(1/3)<BR>\n" );
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document.write( "New volume = (4/3)pi^3<BR>\n" );
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document.write( "New volume = 4 cu in.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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