document.write( "Question 420633: Trains A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and Train B is traveling at 100 miles per hour. Train A passes a station at 9:20 am. If Train B passes the same station at 9:32 am, at what time will Train B catch up to Train A? \n" ); document.write( "
Algebra.Com's Answer #293878 by ankor@dixie-net.com(22740)\"\" \"About 
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Trains A and B are traveling in the same direction on parallel tracks.
\n" ); document.write( " Train A is traveling at 80 miles per hour and Train B is traveling at 100 miles per hour.
\n" ); document.write( " Train A passes a station at 9:20 am.
\n" ); document.write( "If Train B passes the same station at 9:32 am, at what time will Train B catch up to Train A?
\n" ); document.write( ":
\n" ); document.write( "From the given information, we know that train B is 12 min (1/5 hr) behind
\n" ); document.write( " train A, when train A passes the station
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\n" ); document.write( "The distance between the trains at this time: \"1%2F5\" * 100 = 20 mi
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\n" ); document.write( "Let t = time required for train B to catch train A
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\n" ); document.write( "write a distance equation: Dist = speed * time
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\n" ); document.write( "Train B travel dist = Train A travel dist + 20 mi
\n" ); document.write( "100t = 80t + 20
\n" ); document.write( "100t - 80t = 20
\n" ); document.write( "20t = 20
\n" ); document.write( "t = \"20%2F20\"
\n" ); document.write( "t = 1 hr for B to catch A
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\n" ); document.write( "9:20 AM + 1.00 = 10:20 AM, B catches A
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