document.write( "Question 420668: A survey of 4,581 U.S. households that owned a mobile phone found that 58 percent are satisfied with the coverage of their cellular phone provider. (a) Assuming that this was a random sample, construct a 90 percent confidence interval for the true proportion of satisfied U.S. mobile phone owners. (b) Why is the confidence interval so narrow? \n" ); document.write( "
Algebra.Com's Answer #293860 by stanbon(75887) ![]() You can put this solution on YOUR website! A survey of 4,581 U.S. households that owned a mobile phone found that 58 percent are satisfied with the coverage of their cellular phone provider. \n" ); document.write( "---------------------------------------- \n" ); document.write( "(a) Assuming that this was a random sample, construct a 90 percent confidence interval for the true proportion of satisfied U.S. mobile phone owners. \n" ); document.write( "--- \n" ); document.write( "p-hat = 0.58 \n" ); document.write( "ME = 1.645*sqrt[0.58*0.42/4581] = 0.0987 \n" ); document.write( "--- \n" ); document.write( "90%CI: 0.58-0.0987< p < 0.58+0.0987 \n" ); document.write( "--- \n" ); document.write( "90%CI: 0.4813 < p < 0.6787 \n" ); document.write( "-------------------------------\r \n" ); document.write( "\n" ); document.write( "(b) Why is the confidence interval so narrow? \n" ); document.write( "Its width is 2ME and ME is small because the sample size is large. \n" ); document.write( "====================================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " \n" ); document.write( " |