document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=420501>Question 420501</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that $11,000 is investted at an interest rate of 5.9% per year, compounded continuously. What is the doubling time? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293823 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293823\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose that $11,000 is investted at an interest rate of 5.9% per year, compounded continuously. What is the doubling time?<BR>\n" );
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document.write( "A(t) = Ao*e^(rt)<BR>\n" );
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document.write( "2Ao = Ao*e^(0.059t)<BR>\n" );
document.write( "e^(0.059t) = 2<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Take the ln of both sides to get:<BR>\n" );
document.write( "0.059t = ln2<BR>\n" );
document.write( "t = 11.75 years<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============= </SPAN>\n" );
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