document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44490>Question 44490</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to know the radius and center for this equation. It is for cirles. <BR>\n" );
document.write( "4x^2+75x-35y+4y^2=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29378 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29378\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I need to know the radius and center for this equation. It is for cirles.<BR>\n" );
document.write( "4x^2+75x-35y+4y^2=0<BR>\n" );
document.write( "=4(X^2+75X/4-35Y/4 +Y^2)=0<BR>\n" );
document.write( "=[(X)^2+2(X)(75/8)+(75/8)^2]-(75/8)^2+[Y^2-2(Y)(35/8)+(35/8)^2]-(35/8)^2=0<BR>\n" );
document.write( "=[X+(75/8)]^2+[Y-(35/8)]^2=(75^2+35^2)/64=6850/64={82.67/8}^2<BR>\n" );
document.write( "COMPARING WITH STD.EQN.<BR>\n" );
document.write( "(X-H)^2+(Y-K)^2=R^2...WE GET <BR>\n" );
document.write( "CENTRE AS (-75/8,35/8)AND RADIUS AS (82.67/8)=10.33 </SPAN>\n" );
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