document.write( "Question 420355: Asia invested $15,000 and she earned an annul interest of $1350. She put some of the money in the bank at 6% interest per year and invested the rest at 11% interest per year. How much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #293753 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Asia invested $15,000 and she earned an annul interest of $1350. She put some of the money in the bank at 6% interest per year and invested the rest at 11% interest per year. How much did she invest at each rate?
\n" ); document.write( "------------
\n" ); document.write( "Equations:
\n" ); document.write( "Quantity: x + y = 15000
\n" ); document.write( "Interest:0.06x + 0.11y = 1350
\n" ); document.write( "----------------------------------
\n" ); document.write( "Multiply thru the 1st by 6
\n" ); document.write( "Multiply thru the 2nd by 100
\n" ); document.write( "-------------------------------------
\n" ); document.write( "6x + 6y = 6*15000
\n" ); document.write( "6x + 11y = 135000
\n" ); document.write( "---------------------------
\n" ); document.write( "Subtract and solve for \"y\":
\n" ); document.write( "5y = 45000
\n" ); document.write( "y = 9000 (amt invested at 11%
\n" ); document.write( "---
\n" ); document.write( "solve for \"x\":
\n" ); document.write( "x = 15000-9000 = 6000 (amt. invested at 6%
\n" ); document.write( "===================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "===================
\n" ); document.write( "
\n" );