document.write( "Question 420355: Asia invested $15,000 and she earned an annul interest of $1350. She put some of the money in the bank at 6% interest per year and invested the rest at 11% interest per year. How much did she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #293753 by stanbon(75887) ![]() You can put this solution on YOUR website! Asia invested $15,000 and she earned an annul interest of $1350. She put some of the money in the bank at 6% interest per year and invested the rest at 11% interest per year. How much did she invest at each rate? \n" ); document.write( "------------ \n" ); document.write( "Equations: \n" ); document.write( "Quantity: x + y = 15000 \n" ); document.write( "Interest:0.06x + 0.11y = 1350 \n" ); document.write( "---------------------------------- \n" ); document.write( "Multiply thru the 1st by 6 \n" ); document.write( "Multiply thru the 2nd by 100 \n" ); document.write( "------------------------------------- \n" ); document.write( "6x + 6y = 6*15000 \n" ); document.write( "6x + 11y = 135000 \n" ); document.write( "--------------------------- \n" ); document.write( "Subtract and solve for \"y\": \n" ); document.write( "5y = 45000 \n" ); document.write( "y = 9000 (amt invested at 11% \n" ); document.write( "--- \n" ); document.write( "solve for \"x\": \n" ); document.write( "x = 15000-9000 = 6000 (amt. invested at 6% \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=================== \n" ); document.write( " |