document.write( "Question 44499: SUPPOSE THAT THE PERIMETER OF A SQUARE EQUALS THE PERIMETER OF A RECTANGLE. THE WIDTH OF THE RECTANGLE IS 9 INCHES LESS THAN TWICE THE SIDE OF THE SQUARE AND THE LENGTH OF THE RECTANGLE IS 3 INCHES LESS THAN TWICE THE SIDE OF THE SQUARE. FIND THE DIMINSIONS OF THE SQUARE AND THE RECTANGLE. \n" ); document.write( "
Algebra.Com's Answer #29374 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! SUPPOSE THAT THE PERIMETER OF A SQUARE EQUALS THE PERIMETER OF A RECTANGLE. THE WIDTH OF THE RECTANGLE IS 9 INCHES LESS THAN TWICE THE SIDE OF THE SQUARE AND THE LENGTH OF THE RECTANGLE IS 3 INCHES LESS THAN TWICE THE SIDE OF THE SQUARE. FIND THE DIMINSIONS OF THE SQUARE AND THE RECTANGLE. \n" ); document.write( "LET LENGTH OF SIDE =A \n" ); document.write( "LET LENGTH AND WIDTH OF RECTANGLE BE L AND W \n" ); document.write( "PERIMETEROF SQUARE=4A=PERIMETER OF RECTANGLE =2(L+B) \n" ); document.write( "2A=L+B...................I \n" ); document.write( "TWICE SIDE OF SQUARE=2A \n" ); document.write( "9\" LESS =2A-9=W...............II \n" ); document.write( "3\" LESS =2A-3=L.................III \n" ); document.write( "SUBSTITUTING II AND III IN I \n" ); document.write( "2A=2A-3+2A-9 \n" ); document.write( "2A=12 \n" ); document.write( "A=6 \n" ); document.write( "L=2A-3=2*6-3=9 \n" ); document.write( "W=2*6-9=3 \n" ); document.write( " |