document.write( "Question 44499: SUPPOSE THAT THE PERIMETER OF A SQUARE EQUALS THE PERIMETER OF A RECTANGLE. THE WIDTH OF THE RECTANGLE IS 9 INCHES LESS THAN TWICE THE SIDE OF THE SQUARE AND THE LENGTH OF THE RECTANGLE IS 3 INCHES LESS THAN TWICE THE SIDE OF THE SQUARE. FIND THE DIMINSIONS OF THE SQUARE AND THE RECTANGLE. \n" ); document.write( "
Algebra.Com's Answer #29374 by venugopalramana(3286)\"\" \"About 
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SUPPOSE THAT THE PERIMETER OF A SQUARE EQUALS THE PERIMETER OF A RECTANGLE. THE WIDTH OF THE RECTANGLE IS 9 INCHES LESS THAN TWICE THE SIDE OF THE SQUARE AND THE LENGTH OF THE RECTANGLE IS 3 INCHES LESS THAN TWICE THE SIDE OF THE SQUARE. FIND THE DIMINSIONS OF THE SQUARE AND THE RECTANGLE.
\n" ); document.write( "LET LENGTH OF SIDE =A
\n" ); document.write( "LET LENGTH AND WIDTH OF RECTANGLE BE L AND W
\n" ); document.write( "PERIMETEROF SQUARE=4A=PERIMETER OF RECTANGLE =2(L+B)
\n" ); document.write( "2A=L+B...................I
\n" ); document.write( "TWICE SIDE OF SQUARE=2A
\n" ); document.write( "9\" LESS =2A-9=W...............II
\n" ); document.write( "3\" LESS =2A-3=L.................III
\n" ); document.write( "SUBSTITUTING II AND III IN I
\n" ); document.write( "2A=2A-3+2A-9
\n" ); document.write( "2A=12
\n" ); document.write( "A=6
\n" ); document.write( "L=2A-3=2*6-3=9
\n" ); document.write( "W=2*6-9=3
\n" ); document.write( "
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