document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=420241>Question 420241</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I graph y=2+3cos(3x-pi/4)? Thanks for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #293708 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=293708\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I graph y=2+3cos(3x-pi/4)? Thanks for your help!\r<BR>\n" );
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document.write( "y=2+3cos(3x-pi/4)\r<BR>\n" );
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document.write( "Wish I could draw a diagram for you but,I will have to do it with words.\r<BR>\n" );
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document.write( "By inspection of the given expression, the amplitude=3, and the curve will be bumped up 2 units.<BR>\n" );
document.write( "Period = 2pi/B=2pi/3=(2/3)pi or  (B=the coefficient of x)<BR>\n" );
document.write( "Phase Shift:<BR>\n" );
document.write( "set 3x-pi/4=0<BR>\n" );
document.write( "then solve for x<BR>\n" );
document.write( "3x=pi/4<BR>\n" );
document.write( "x=pi/12=(1/12)pi=phase shift<BR>\n" );
document.write( "Divide period into four intervals<BR>\n" );
document.write( "2pi/3*1/4=pi/6 <BR>\n" );
document.write( "1/4 period=(1/6)pi or (2/12)pi\r<BR>\n" );
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document.write( "drawing the graph for one period:\r<BR>\n" );
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document.write( "On the x-axis, mark point (1/12)pi (this is where the cos graph starts)<BR>\n" );
document.write( "mark the second point on the x-axis which will be (3/12)pi (we added a quarter point to the starting point. Add a quarter point for the third point, (5/12)pi.<BR>\n" );
document.write( "The fourth and 5th points will then be (7/12)pi and (9/12) pi. Note that from the first point, (1/12)pi to the fifth point (9/12) we covered one period=(8/12)pi. We can now draw the cos curve.The ordered pairs will be:<BR>\n" );
document.write( "(pi/12,5),(pi/4,0),(5pi/12,-1,),(7pi/12,0), and (9pi/12,5).<BR>\n" );
document.write( "The graph below will give you some idea what we did: Remember, the cos function goes on forever, but we did it for only one period.\r<BR>\n" );
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